Hi.
The 8V97051L datasheet specifies 21 mA as typical current consumption for the V_CP rail. This is when ICP is set to 0.31 mA.
How much will V_CP's current consumption increase if ICP is set to 5 mA? I don't need an exact figure but it would help if I knew that it increases by 1, 10 or 100 mA.
Regards
Smurfigast,
Icp is charge pump current. Icp is programmable from 310μA to 5mA.
increasing the charge pump current to ICP~5mA (ICP setting = 1111 or 16 times the normal charge pump current). Thecombination of the R4 and R5 in parallel is 1/4 * Rs.
My question was regarding V_CP current consumption vs ICP. I can't see that you answered that question
It is directly relative - the current draw will increase by roughtly 4mA.